7x^2+4x+13=5

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Solution for 7x^2+4x+13=5 equation: 



7x^2+4x+13=5

We move all terms to the left:

7x^2+4x+13-(5)=0

We add all the numbers together, and all the variables

7x^2+4x+8=0

a = 7; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·7·8
Δ = -208
Delta is less than zero, so there is no solution for the equation

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